Re: commit inserts made in SQL procedure

COMMIT = *CHG

Doesn't auto commit.

You'd need to issue the commit yourself.

The system doesn't have an auto-commit AFAIK, closest is COMMIT = *NONE.

I believe there's an "auto commit" in various tools. For instance, ACS Run
SQL scripts has a "enable true autocommit" setting. But that's a function
of the JDBC driver.
; basically after every successful statement, a COMMIT is implicitly run by
the driver.



On Tue, Sep 5, 2017 at 10:19 AM, Steve Richter <stephenrichter@xxxxxxxxx>
wrote:

running an SQL procedure that creates a new table from the resulting rows
of a select statement. The code runs, but then when I signoff the system
is deleting the table. I guess because of commitment control.

how do I commit changes made in an SQL procedure?

I am using "set option commit = *chg" . Which I read says the sql
procedure should auto commit its changes. But the auto commit is not
happening.

Running the COMMIT command, the system comes back and says COMMIT defn

not

found. But I WRKJOB option 16 commitmet control status, and there are

two

committment definitions.

Commitment
Definition Text
APLUS Activation-group-level
QDBAGILE Activation-group-level


here is the SQL procedure:
CREATE or replace PROCEDURE SRICHTER/cca_hsdetCca(
)
LANGUAGE SQL
MODIFIES SQL DATA
set option commit = *chg
BEGIN atomic

declare vSqlCode decimal(5,0) ;
declare sqlCode int DEFAULT 0 ;
DECLARE VMSG CHAR(256) ;
DECLARE VCMDSTR CHAR(256) ;
DECLARE DUMMY INTEGER ;
declare vPrCatNum int ;

create table srsql/hsdetcca as (
select a.*, b.cmcscl cscl, b.cmcssc cssc
from hsdetv1 a
join cusms b on a.csno = b.cmcsno and b.cmcono = 1
where b.cmcscl = '05' and year(a.ivdate) >= 2016
and a.litp = 'I' or ( a.litp = 'C' and a.itno = '&6' )
) with data ;

END
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