You'll have to write a routine that converts the value between base36 and
back again. You can define the order of the digits however you'd like in a
string array. The logic of the conversion will be the complicated part,
but I would suppose google could steer you in the right direction on how to
write such a routine.
From: Gad Miron <gadmiron@xxxxxxxxx>
To: midrange-l@xxxxxxxxxxxx
Date: 06/17/2015 01:44 AM
Subject: The case of outnumbered numerator
Sent by: "MIDRANGE-L" <midrange-l-bounces@xxxxxxxxxxxx>
Hello Pundits
We have a six digits numerator that approaches 899999.
Since it happens to be a CHAR field I would like to start using the
letters A-Z
in lexical order when incrementing this field so that incrementing
899999 will result in 9AAAAA , 9AAAAB , ......., 9AAAAZ, 9AAAA0, 9AAAA1
etc.
(This way the numerator will sort the EBCDIC natural way)
Do you know an *elegant* way of doing it ?
(EBCDIC table having "holes" of unprintable chars does not expedite
matters)
Thanks
Gad
--
This is the Midrange Systems Technical Discussion (MIDRANGE-L) mailing list
To post a message email: MIDRANGE-L@xxxxxxxxxxxx
To subscribe, unsubscribe, or change list options,
visit:
http://lists.midrange.com/mailman/listinfo/midrange-l
or email: MIDRANGE-L-request@xxxxxxxxxxxx
Before posting, please take a moment to review the archives
at
http://archive.midrange.com/midrange-l.
midrange.com
