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I want to extract record from a file where a field matches a
pattern. To do so, I use the « LIKE » instruction in the WHERE
clause. Here is a strip down version:
@patern = '%' + %trim(@filter) + '%';
exec sql declare cur_next_filter cursor for
select ch1 from nozzzdp
where dsl like :@patern ;
...
exec sql fetch from cur_next_filter into :ds_key;
The value of the @filter variable is "A" (I want everything with an
A in the dsl variable)
This does not retrieve any value (sqlstt = 2000)
<<SNIP>>
Any help will be appreciated
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