|
*This message was transferred with a trial version of CommuniGate(r) Pro*
Good evening
Here is the situation
V5R4 System
QSTRUP in QGPL is defined in sysval
System is IPLed and the QSTRUP aborts on line 73
Message ID . . . . . . : CPA0701 Severity . . . . . . . : 99
Message type . . . . . : Inquiry
Date sent . . . . . . : 09/06/13 Time sent . . . . . . : 21:35:13
Message . . . . : CPF1010 received by QSTRUP at 7300. (C D I R)
Cause . . . . . : Control language (CL) program QSTRUP in library QGPL
detected an error at statement number 7300. Message text for CPF1010 is:
Subsystem name ZMPLUS active.
Recovery . . . : This inquiry message can be avoided by changing the
program. Monitor for the error (MONMSG command) and perform error recovery
within the program. To continue, choose a reply value.
Possible choices for replying to message . . . . . . . . . . . . . . . :
C -- Cancel the CL program.
D -- Dump the CL program variables and cancel the CL program.
I -- Ignore the failing command.
I looked at the QCLSRC in QGPL for QSTRUP and looked for line 73
There was no line 73 It ended at line 63
I know the problem, source and object are not the same
I did a RTVCLSRC and named it QSTRUP2
I went in and looked at the source code and the 2 source codes were the
same.
I compiled QSTRUP2 and the printout of the compiled program only shows 63
lines
How can I have a program abort on line 73 with only 63 lines in the total
program?
Thanks in advance
Dave Willenborg
FNTS
Omaha NE
As an Amazon Associate we earn from qualifying purchases.
This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.