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Yep. Most of the time "as" is optional; this time it's not.

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Scott Mildenberger
Sent: Friday, March 29, 2013 4:59 PM
To: Midrange Systems Technical Discussion
Subject: RE: trying to join twice

Missing as before p.

Scott

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Stone, Joel
Sent: Friday, March 29, 2013 3:58 PM
To: 'Midrange Systems Technical Discussion'
Subject: trying to join twice

Receive error as shown on last line.

Can this be done?

Thanks

select
a.ACNTNMB,s.sumAFNLAPL,s.sumAESTAPL,AOPNBLA,ATRMQNT,
ATRMQNT - AOPNBLA
from conterms as a
inner join
lateral (
select b.acntnmb
,sum(b.AFNLAPL) as sumAFNLAPL
,sum(b.AESTAPL) as sumAESTAPL
from applsjct as b
where b.ASHPTYR = '13'
and a.ACNTNMB = b.ACNTNMB
and a.ADVSNCD = b.ADVSNCD
group by b.ACNTNMB
) as s
on a.ACNTNMB = s.ACNTNMB
inner join applship p
on p.ASHPNBR = s.ASHPNBR
p.ABLDNGD = s.ABLDNGD
p.APLSQNB = s.APLSQNB


where s.sumAESTAPL <> ATRMQNT - AOPNBLA




Token P was not valid. Valid tokens: FOR WITH FETCH ORDER UNION EXCE



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