Sorry there isn't a function like AVG that will calculate a median value for
you directly. Although you could probably write a UDF to do it. Here's
what I have used to calculate one...
select x.FIELDNAME from LIBRARY/FILE x, LIBRARY/FILE y
group by x.FIELDNAME
having sum(case when y.FIELDNAME <= x.FIELDNAME then 1 else 0
sum(case when y.FIELDNAME >= x.FIELDNAME then 1 else 0 end)>=(count(*)/2)+1
The value returned is the median value of FIELDNAME in the file.
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Smith, Mike
Sent: Thursday, March 29, 2012 12:58 PM
To: 'Midrange Systems Technical Discussion'
Subject: sql with averages and medians
I have the following sql statement
SELECT PE1DPT,PEMEMP, PEMNAM , integer(floor(current_date -
getdatesql(PEMBDT))/10000) as age,
integer(floor(current_date -getdatesql(PEMHDT))/10000) as YOS FROM premp,
WHERE PEMEMP = PE1EMP and PEMEES = 'FR'
ORDER BY age desc
I want to create another sql statement that is based on the previous but
gives me # of employees by dept(PE1DPT), Average age(AGE), Median Age(AGE),
Average Service(YOS) , and median service(YOS)
So I've got this.
SELECT PE1DPT, count(*) , avg(integer(floor(current_date -
getdatesql(PEMBDT))/10000)) as age,
avg(integer(floor(current_date - getdatesql(PEMHDT))/10000)) as YOS FROM
premp, prei1 WHERE .PEMEMP = .PE1EMP and PEMEES = 'FR'
GROUP BY pe1dpt
I can't seem to figure out how I might get the median for age and yrs of
Anyone know how to do this?
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