Re: Xerox 5135 drawer select

I am looking at the WSCST. Friday, I actually did try your
suggestion. It went back to the bypass tray. I had hoped that I had
not tried this.

Other details: System driver program is IBMSNMPDRV, and MFRTYPMDL is
*LEXOPTRAT.

I did have drawer select for drawer one same as drawer 3. I removed
that, recompiled, stopped writer, varied off and on the device,
started writer, and ...same result.

Any other suggestions?

John McKee


On Sun, Mar 4, 2012 at 7:38 PM, CRPence <CRPbottle@xxxxxxxxx> wrote:

  The PCL DATA is represented by an ASCII string often described as:
      <esc> & l int H

  The above is often referred to in the IBM documentation as the
"Command (ASCII Text)" represented in a slightly different form [e.g.
Ec&l4H where int=4]:
      Ec & l int H

  The Bypass Tray was noted to be represented with the ASCII string in
hex notation:
     '1B266C3248'X

  Breaking down the above string, for each ASCII character:
   <esc>=0x1B, '&'=0x26, 'l'=0x6C, int=(2=Bypass Tray)='2'=0x32, 'H'=0x48

  For HCI-Tray=2 the corresponding "int" value apparently should be 20,
and presumably the value 21=(Tray 3 [High Capacity]).  As such, the
ASCII string [for the DATA= ASCII control sequence] in hexadecimal
notation for the HCI-Tray=3 as I understand should be:
     '1B266C323148'X

  Breaking down the above string, for each ASCII character:
   <esc>=0x1B, '&'=0x26, 'l'=0x6C, int=(21=Tray 3 [HCI])='21'=0x3231,
'H'=0x48

Regards, Chuck

On 02-Mar-2012 11:38 , John McKee wrote:

I have made considerable progress, but have hit a wall.

I downloaded a reference to PCL. Under Paper (Media) Source, I saw
the code to explain why the bypass tray was being used. The WSCST had
this for DRAWER=PAPER: DATA = '1B266C3248'X.

The second from the right hex chars x'32' command "Feed paper from
manual input".

I changed that to 31. Now, draws from drawer 1. At the bottom of the
codes for paper source is this entry:

20 -39 High Capacity Input (HCI) Trays 2-21.

Since I need tray 3, it seemed simple. If tray 2 is 20, then tray 3
must be 21.

So, I converted 21 (assumed decimal, based on 32 being ASCII value of
2 for manual input) to 15.

That didn't work. Printer rejected that sequence.

So, question is (feels like snatching defeat from the jaws of
victory), what goes into that position?

I know this is not an IBM issue. I found another 5135 that they also
would very much like to use tray 3. I'm just not understanding what
that value should be.

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