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I have a file that contains 2 separate numeric fields, that when combined
create a 6 digit date in MMDDYY format (NOT my idea - it is what it is)
The fields are
Fieldmmdd 4 0
Fieldyy 2 0
When I use the following SQL command
select * from FILEA where
DATE(substr(digits(fieldmmdd), 1, 2) concat '/' concat
substr(digits(fieldmmdd), 3, 2) concat '/' concat
digits(fieldyy)) > current_date - 3 months
this results in the following
Selection error involving field FIELDMMDD.
I then tried the following
select * from FILEA where
substr(digits(fieldmmdd), 1, 2) between '01' and '12' and
DATE(substr(digits(fieldmmdd), 1, 2) concat '/' concat
substr(digits(fieldmmdd), 3, 2) concat '/' concat
digits(fieldyy)) > current_date - 3 months
with the same result
My thinking is that the data results in an invalid date.
How do I find those records with the invalid date?
I tried
select * from FILEA
DATE(substr(digits(fieldmmdd), 1, 2) concat '/' concat
substr(digits(fieldmmdd), 3, 2) concat '/' concat
digits(fieldyy)) is null
with the same result
Selection error involving field FIELDMMDD
As always, all replies gratefully accepted
Please note
I did try the following
select fieldmmdd, fieldyy,
DATE(substr(digits(fieldmmdd), 1, 2) concat '/' concat
substr(digits(fieldmmdd), 3, 2) concat '/' concat
from FILEA
which DID display data, but as the file is LARGE (couple of hundred
million), I'm pretty sure the display of data will help
Alan Shore
Programmer/Analyst, Direct Response
E:AShore@xxxxxxxx
P:(631) 200-5019
C:(631) 880-8640
"If you're going through Hell, keep going" - Winston Churchill
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