AW: SQL Date function question

In my opinion the solution using the scalar function (Chuck already proposed
yesterday) is the most "elegant" way:

right(VarChar(MyFld), 4)

It will return 2011 out of 112011, 3122011 and 12312011

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"


-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von Bradley Stone
Gesendet: Thursday, 07. July 2011 15:29
An: Midrange Systems Technical Discussion
Betreff: Re: SQL Date function question

My apologies to those that actually supplied the digits solution. I
was getting bombarded with answers and I mistakingly assumed the
DIGITS function wouldn't zero pad the number returned, and also
getting frustrated since I originally explained it wrong, but tried to
correct that a couple times and people were still commenting on the
original error. :)

All I needed to do in the end was change substr(char(field),5,4) to
substr(digits(field),5,4) and it worked like a charm (and a lot less
messy than my original solution).

Thanks again!

Brad

On Thu, Jul 7, 2011 at 7:15 AM, Charles Wilt <charles.wilt@xxxxxxxxx> wrote:

Yeah, I gave him the DIGITS solution 14 hours ago...but it was at the
bottom my reply....

Charles

On Thu, Jul 7, 2011 at 8:08 AM,  <rob@xxxxxxxxx> wrote:

I truly think that Brad is skimming the answers and is not reading them
thoroughly.

Brad, if you use digits instead of cast, or char, you will be fine.  You
will still have your leading zero.  If you use Alan Campin's iDate
function it will work.  Have faith.


Rob Berendt
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