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That was just a best guess. Not all of my Java knowledge ports backwards to C.

how about printf((char)0x0D)?
That actually makes more sense to me than what I typed the first time around.

Jason Abreu
Abreu Innovations, Inc.
jason.abreu@xxxxxxxxxxxxxxxxxxxx
http://www.abreuinnovations.com/

On 3/10/2011 9:18 AM, Dennis Lovelady wrote:
Thank you for your response, Jason.

printf('0x0d') returns CZM0076: Character constant '0x0d' has more than
one character....
Same with '0x0a' of course. printf requires a pointer as the first
parameter.

What I think you meant:<< printf("%c", 0x0d); printf("%c", 0x0a)>>
causes output of 0x0d8e. (Yeah, really.)

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