RE: Level check problem - chgpf

Where you went wrong was in changing the two files independently. The
system uses timestamp to generate the format level ID, and the timestamps of
the two files cannot match. It doesn't matter that the format names, field
names etc. are the same since those don't generate the format level ID.

To correct this, create a new log file and repopulate it. Then eliminate
the old (save it first). Here's one way:

CPYF lib/DATAFILE lib/NEWLOG CRTFILE(*YES) TOMBR(some_unique_value)
CPYF lib/OLDLOG lib/NEWLOG FROMMBR(*ALL) TOMBR(*FROMMBR) FMTOPT(*MAP)
RNMOBJ lib/OLDLOG *FILE SAVEME
RNMOBJ lib/NEWLOG *FILE OLDLOG

Or thereabouts.

Dennis Lovelady
http://www.linkedin.com/in/dennislovelady
--
"The direct use of force is such a poor solution to any problem, it is
generally employed only by small children and large nations."
-- David Friedman

I started out with one data file and a log-file that was created as a
copy of same file (CRTDUPOBJ). The log file has then been changed to
allow multiple members.



Now when new fields had to be added to the data file we also had a need
to keep the log file format in synch.



I did a CHGPF of the log file with the SRCFILE parameter and indicated
the source member that was used for the re-compile of the data file.



As far as I can see both files have the same record size, fields, field
types and field lengths.



Despite this I get a level check when using the CPYF to copy data from
one file to the other.



Where did I go wrong - OR is the only safe way to reformat files the
old trusted way of recompile and manual copying of the data?



File level id:s:

Data file 1100813084024

Log file 1100813084348



Format id:

Data file 42A0FD7F7A38F

Log file 42A0FD7F7A38F







Med vänlig hälsning / Best regards


Åke H Olsson



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