Re: SQL Sum(Distinct()) -- MIDRANGE-L

I forgot to say thank you, so Thank You!

This list is fabulous.

On Mon, Jun 21, 2010 at 11:11 AM, Birgitta Hauser <Hauser@xxxxxxxxxxxxxxx>wrote:

Hi,

you may try something like this:

Exec SQL
Select Sum(D.ITNSA), Sum(H.ORDAM)
Into :Fld1, :Fld2
From OrdHdr h join (Select Oncru, sum(ITNSA) ITNSA
From OrdDtl
Group By ONCRU) d
On h.Oncru = d.Oncru
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"

-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von Jeff Crosby
Gesendet: Monday, 21. June 2010 16:33
An: Midrange Systems Technical Discussion
Betreff: SQL Sum(Distinct())

Been a while since I've asked an SQL question, so I'm due. :)

I will soon, I think, have a need within an RPG program to get a couple of
pieces of summary information from an order header/detail pair of files.
One piece from the header file and one piece from the detail file. I can
get the 2 pieces separately like this:

Exec SQL
Select SUM(ORDAM)
Into :ORDAM
From ORHDR
Where CUSNR = :CUSNR and
ROUTE = :ROUTE and
STOPX = :STOPX and
SHPDTISO = :SHPDTISO;

Exec SQL
Select SUM(d.ITNSA)
Into :ITNSA,
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

I wondered if I could get the 2 pieces with a single statement, so I tried
this:

Exec SQL
Select SUM(d.ITNSA),
SUM(h.ORDAM)
Into :ITNSA,
:ORDAM
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

It executed, but the RPG field ORDAM was waAAAyyy off because field h.ORDAM
from the header file was summed for each record in the detail file. I
understand why that is and it makes sense. I did some googling and came up
with this, using Distinct:

Exec SQL
Select SUM(d.ITNSA),
SUM(Distinct(h.ORDAM))
Into :ITNSA,
:ORDAM
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

That seemed to me like it would have a problem, because 2 selected order
header records COULD have the same h.ORDAM value. Won't happen often, but
it can and does happen sometimes. If I understand Distinct right, it would
only include one of them in the Sum function. So I did some testing and
found that to be true.

So is there a way to do what I want in one statement? The flip side of
that
is, if the statement is very complex, I would rather do it in 2 statements
because I believe in KISS.

Thanks.

--
Jeff Crosby
VP Information Systems
UniPro FoodService/Dilgard
P.O. Box 13369
Ft. Wayne, IN 46868-3369
260-422-7531
www.dilgardfoods.com

The opinions expressed are my own and not necessarily the opinion of my
company. Unless I say so.
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