DLFM question

Hi all,

Anyone know how to stop this?
My client reports that when he starts all TCP servers, he is now getting a
'terminal session' of DLFM which reports 'error receiving message from
DLFM server', and he has to press enter to end the session. I can't see
where to change attributes of this server, or what has changed as this
used not to happen!
Thanks for any insights,

cheers,

Clare

Evan Harris wrote:

Hi Terry

My first thought would be to use 2 regexes - the first to extract the substring you want to perform the second on.

So in your case, something like

"n(u)(t*i)"
"(t*)(i)"

But I don't get what you are trying to accomplish so I have no idea if this is applicable.

After reading the manual extract posted doing it this way may at leads give me mortals a chance of understanding what you are trying to do.


Regards
Evan Harris


-----Original Message-----
From: [1]midrange-l-bounces@xxxxxxxxxxxx [[2]mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Terrence Enger
Sent: Tuesday, 4 August 2009 7:21 a.m.
To: Midrange Systems Technical Discussion
Subject: Re: [Fwd: regular expressions, I am puzzled]

On Mon, 2009-08-03 at 12:22 -0500, Scott Klement wrote:


Hi Terry,

Have you read the following (from regexec topic in the "ILE C Runtime
Library" manual):

If subexpression i is contained within another subexpression j, and i
is not contained within any other subexpression that is contained
within j, and a match of subexpression j is reported in pmatch[j],
then the match or non-match of subexpression i reported in pmatch[i]
will be as described in 1. and 2. above, but within the substring
reported in pmatch[j] rather than the whole string.


No, I should have been following that. Thank you.

In a simple case, I see that behaviour: regex "nu((t*)(i))" and string
"nuttin" return
rm_so rm_eo
----- -----
2 5
0 2
2 3

Introduction of a set of parentheses earlier in the regex should not, as
I read it, change the result returned for the last two subexpressions.
But the result for regex "n(u)((t*)(i))" is
rm_so rm_eo
----- -----
1 2
2 5
1 3
3 4

Thank you for your help, Scott. Any further thoughts?

Terry.





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