× The internal search function is temporarily non-functional. The current search engine is no longer viable and we are researching alternatives.
As a stop gap measure, we are using Google's custom search engine service.
If you know of an easy to use, open source, search engine ... please contact support@midrange.com.



Ok, got it working. Had to change from
UNION
to
UNION ALL

SELECT assumes ALL and not DISTINCT
UNION assumes DISTINCT and not ALL

So, now this:
with t1 as (
select 'D' as RecType, Dude, Moola as Money
from qtemp.thoma),
t2 as (
select 'S' as RecType, Dude, sum(Moola) as Money
from qtemp.thoma
group by Dude,1)
select * from t1
union ALL
select * from t2
order by Dude, RecType, Money

Returns:
....+....1....+....2....+....
RECTYPE DUDE MONEY
D Tom 100
D Tom 100
S Tom 200
D Will 50
D Will 200
S Will 250
******** End of data ******

Rob Berendt

As an Amazon Associate we earn from qualifying purchases.

This thread ...

Replies:

Follow On AppleNews
Return to Archive home page | Return to MIDRANGE.COM home page

This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].

Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.