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-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Michael Ryan
Sent: Friday, August 17, 2007 12:05 PM
To: Midrange Systems Technical Discussion
Subject: Re: SQL SELECT with Similar Terms
Wow...two ways to do something I didn't think could be done.
Is this list great or what?
On 8/17/07, BirgittaHauser <Hauser@xxxxxxxxxxxxxxx> wrote:
Hi,mytable group
I prefere the scalar function TRIM:
select trim(Both ':' from RTrim(MyField)), count(*) from
by Trim(Both ':' from RTrim(MyField))the stars."
Mit freundlichen Grüßen / Best regards
Birgitta Hauser
"Shoot for the moon, even if you miss, you'll land among
(LesNot training
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them?
them and keeping them!"Vernon Hamberg
-----Ursprüngliche Nachricht-----
Von: midrange-l-bounces@xxxxxxxxxxxx
[mailto:midrange-l-bounces@xxxxxxxxxxxx] Im Auftrag von
Gesendet: Friday, August 17, 2007 15:41mryan group by
An: Midrange Systems Technical Discussion
Betreff: Re: SQL SELECT with Similar Terms
Michael
Based on another recent post, here's a way to get what you want--
select strip(translate(char20,' ', ':')), count(*) from
strip(translate(char20,' ', ':'))please take
If you had more punctuations, just add them to the 3rd parameter of
translate().
HTH
Vern
At 08:18 AM 8/17/2007, you wrote:
Anyone know how to do this? I have data that looks like this:
Rattan
Traditional
:Rattan:
Contemporary
I'd like to produce a list like
Rattan 2
Traditional 1
Contemporary 1
The 'extra' search result with the colons around it should be the
same as the search result without the colons.
Thanks...
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