RE: SQL - multiple rows for same customer, but only want earliest one

Depends, need more info on the columns/keys...

Here's one:

With earliestTran as (select custNbr, min(trandate) as firstDate
                      from myFile
                     )

Select mf.*

From myFile mf, earliestTran et

Where mf.custNbr = et.custNbr
  and mf.tranDate = er.firstDate


This assumes that only 1 record exists for the customer with a given
date.

HTH,

Charles Wilt
--
iSeries Systems Administrator / Developer
Mitsubishi Electric Automotive America
ph: 513-573-4343
fax: 513-398-1121
  

-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx 
[mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Dan
Sent: Thursday, January 11, 2007 2:47 PM
To: Midrange Systems Technical Discussion
Subject: SQL - multiple rows for same customer, but only want 
earliest one

I think I need an SQL boot camp.

I know this can be done, but the reference and/or programming 
guide need a
"If you want to do *this*, go here" type of chapter.

I have a select for which multiple rows can be returned for the same
customer number, but I only want the row that has the 
earliest transaction
date.  It appears that DISTINCT will not return an entire 
row, and neither
does MIN.  What am I missing?

TIA,
Dan
-- 
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