Re: Calculating difference between dates in SQL

You need to convert your numeric into a date format.  The best syntax I 
have found is to go through the timestamp function.

date( timestamp( digits(hhdob) || '000000' ) )

Mark

date: Wed, 30 Aug 2006 10:55:23 -0500
from: "Dave Boettcher" <DBoettch@xxxxxxxxxxxxxxxx>
subject: Calculating difference between dates in SQL

hello, 

I have been experimenting with interactive SQL to try to formulate a
statment for later use.

What I need to do is calculate an age for a client . The client master
contains the birth date in numeric form 8,0.

My statement, culled from various books and articles looks like this:

SELECT 
days(current date) - days(date(hhdob)) 
"Age" , 
hhdob, hhnaml, hhnamf, 
  hhcase FROM ClientMaster

The result always seems to look like this:

        "Age"   BIRTH YYYYMMDD            case 
++++++++++++++    19,820,926                 4 
++++++++++++++    19,820,924                 5 
++++++++++++++    19,840,909                 6 
++++++++++++++    19,820,915                 7 
++++++++++++++    19,820,806                 8 
++++++++++++++    19,810,108                 9 
++++++++++++++    19,820,330                10 

From reading it seems like age should be a number, why can't I see it?

Thanks in Advance for any help, 

Dave Boettcher