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The fact that is avoiding the contents of your "IF" statement makes It look like your "IF" statement might be returning false, one thing you could do is replace " argc < 3 || argc > 4" with something that MUST be true for example "1=1". On the other hand it does not pick up where the IF statement ends, so this probably is not it, still I might give it a try because it would only take a second. Chris -----Original Message----- From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Lindbom, Joakim Sent: Wednesday, May 10, 2006 10:02 AM To: Midrange Systems Technical Discussion Subject: Debugger driving off the road Hi! I have a severe problem with the ILE source debugger. The debugger doesn't follow the program logic! There's no warning that there's a source mismatch. An example: 1 printf ("argc: %d", argc); 2 if (argc < 3 || argc > 4) { 3 sprintf (sText, "Internal failure in trigger program (KOF04C). Abending!"); 4 sprintf (lText, "Usage: CALL KOF04C partner library filename <member>\nIf member not passed, *ALL will be used"); 5 AddLogText (&Lh, "main", SEV_FATAL, sText, lText); 6 exit(1); } 7 ExtendString (sPartner, argv[1], sizeof(sPartner)); 8 ExtendString (sLibrary, argv[2], sizeof(sLibrary)); 9 ExtendString (sFile, argv[3], sizeof(sFile)); In this example argc=2 and the expected flow would be: 1, 2, 3, 4, 5, 6 but what happends is 1, 2, 9 Any clues? I don't expect this to be C specific, I've seen the same with ILE RPG /Joakim This message contains information that may be privileged or confidential and is the property of the Capgemini Group. It is intended only for the person to whom it is addressed. If you are not the intended recipient, you are not authorized to read, print, retain, copy, disseminate, distribute, or use this message or any part thereof. If you receive this message in error, please notify the sender immediately and delete all copies of this message.
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