|
If you insist on SQL, basic Boolean logic still helps: > From: darren@xxxxxxxxx > > C* multiply by duty rate percentage > C+ ifnull(case > C+ when :FEDATE>=F4COOD > C+ then 0 > C+ when :FEDATE<F4COOD > C+ and FLPROF='Y' > C+ then FLPROR > C+ when :FEDATE<F4COOD > C+ and FLPROF<>'Y' > C+ then FLNORR > C+ end,0) Can be replaced by this: C* multiply by duty rate percentage C+ ifnull(case C+ when :FEDATE>=F4COOD C+ then 0 C+ when FLPROF='Y' C+ then FLPROR C+ else FLNORR C+ end, 0) I'm not sure of the effect on performance; it would depend on how smart the SQL engine is. Joe
As an Amazon Associate we earn from qualifying purchases.
This mailing list archive is Copyright 1997-2025 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.