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&newdrvf is defined as 10 long Your substring starts in position 5 for 10 characters, which puts it ending in position 14 which is longer than your result field. Thanks, Mark Mark D. Walter Senior Programmer/Analyst CCX, Inc. mwalter@xxxxxxxxxx http://www.ccxinc.com "Dwayne Allison" <Dwayne.Allison@A ffirmativeInsuran To ce.com> "Midrange Systems Technical Sent by: Discussion" midrange-l-bounce <midrange-l@xxxxxxxxxxxx> s@xxxxxxxxxxxx cc Subject 04/13/2005 09:42 Error in coding CPD0895 AM Please respond to Midrange Systems Technical Discussion <midrange-l@midra nge.com> What's wrong with this coding? DCL VAR(&ACTDAT) TYPE(*CHAR) LEN(6) DCL VAR(&NEWDRVF) TYPE(*CHAR) LEN(10) 0000.45 1206- CHGVAR VAR(%SST(&NEWDRVF 1 4)) VALUE('WEDR') 0000.46 1207- CHGVAR VAR(%SST(&NEWDRVF 5 10)) VALUE(&ACTDAT 0000.47 * CPD0895 30 Length and start position will extend past '&NEWDRVF '. -- This is the Midrange Systems Technical Discussion (MIDRANGE-L) mailing list To post a message email: MIDRANGE-L@xxxxxxxxxxxx To subscribe, unsubscribe, or change list options, visit: http://lists.midrange.com/mailman/listinfo/midrange-l or email: MIDRANGE-L-request@xxxxxxxxxxxx Before posting, please take a moment to review the archives at http://archive.midrange.com/midrange-l.
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