Re: SELECT * FROM contralb WHERE pqmad LIKE '%%%'

["Steve Landess" <sjl_123@xxxxxxxxxxx>]

Ted,

This will also work:

SELECT * FROM contralb
WHERE LOCATE('%' , pqmad) <> 0

Steve

----- Original Message -----
From: "Ted Barry" <>
To: <midrange-l@xxxxxxxxxxxx>
Sent: Friday, January 30, 2004 5:49 PM
Subject: SELECT * FROM contralb WHERE pqmad LIKE '%%%'


> I've got a situation with a 'mailing address' field and the % sign is what
I'm looking for.  However, this statement doesn't seem to work:
>
>   SELECT * FROM contralb WHERE pqmad LIKE '%%%'
>
> What am I doing wrong here?  I've tried wrapping it with " and ''%''.
>
>
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