RE: Virtual IP for Failover Questions

[Chris Bipes <chris.bipes@xxxxxxxxxxxxxxx>]

I am running a Virtual IP on my iSeries at 5.1 and it is not in the same
subnet as the physical adapters.

example: 10.99.99.1  = Virtual IP
         10.1.1.1    = Physical IP #1
         192.168.1.1 = Physical IP #2

Dft router for each subnet as a route like this:
10.99.99.1 255.255.255.255 10.1.1.1 metric 1 for the 10.1.1.0 /
255.255.255.0 subnet ( local interface)
10.99.99.1 255.255.255.255 10.1.1.254 metric 3 - router to 192.168.0.0
subnet (remote subnet)

10.99.99.1 255.255.255.255 192.168.1.1 metric 1 for the 192.168.1.0 /
255.255.0.0 subnet (local interface)
10.99.99.1 255.255.255.255 192.168.254.254 metric 3 - router to 10.1.1.0
subnet (remote subnet)


As you see both default routers also have a route to the other subnets so if
the primary is down, they go thru the router that ties the two subnets
together

-----Original Message-----
From: CWilt@xxxxxxxxxxxx

All,

I've successfully setup Virtual IP as describe in the Infocenter here:
http://publib.boulder.ibm.com/iseries/v5r2/ic2924/index.htm?info/rzajw/rzajw
lbvip.htm

Basically, a single Virtual IP on the same subnet as my two Ethernet
adapters.

However, I'm wondering if the following is possible:
1) Multiple Virtual IP address
2) Virtual IP address that are not on the same subnet as (some/all) the
physical adapters.


I have a feeling that #2 isn't possible.  But I'm thinking #1 may well be
possible.  Before I start playing around with this I was wondering if anyone
had any tried doing this.


In case you're wondering why I need this.  The iSeries clients are connected
via 1 of three a specified IP address and are not using DNS.  So in order
for the clients to start using the virtual IP address without manually
reconfiguring them I need to make all three current IPs virtual and assign
new IPs to the adapters.

The different subnet question is because I don't have 3 new IP address on
the original subnet to assign to the adapters.

FYI: I am not the guy who set up the network!  :-)