Good News Everybody!
The new search engine is LIVE!
Please report any problems to david (at) midrange.com.
|
Then how about: Select KEYFIELD, COUNT(*), MAX(RRN(TABLE)) >From COLLECTION.TABLE Group by KEYFIELD Having COUNT(*)>1 For each record in the result set, chain by RRN and delete. Keep running until result set is empty. > -----Original Message----- > From: Mark Allen > > Actually what I need it to do is delete the dups: > > Record 1: ABCDEFGHIJKL > Record 2: ABCDEFGHIJKL > Record 3: 123456789012 > > I want to delete record 2 > > [mailto:midrange-l-bounces@xxxxxxxxxxxx] On Behalf Of Metz Zak > > Well here's your SQL method and I thinks it's pretty clean: > > Select KEYFIELD, COUNT(*) > >From COLLECTION.TABLE > Group by KEYFIELD > Having COUNT(*)>1 NOTICE: This E-mail may contain confidential information. If you are not the addressee or the intended recipient please do not read this E-mail and please immediately delete this e-mail message and any attachments from your workstation or network mail system. If you are the addressee or the intended recipient and you save or print a copy of this E-mail, please place it in an appropriate file, depending on whether confidential information is contained in the message.
This mailing list archive is Copyright 1997-2026 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.