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corretion:
here is how I call the procedure:

callp     $rtvRef('USR' :@userID :DSTUSR)


note: DSTUSR is a data structure.  The procedure will work correctly, if I 
change the caller program to define DSTUSR as a char field.


-----Original Message-----
From: Lim Hock-Chai
Sent: Wednesday, December 18, 2002 9:52 AM
To: midrange-l@midrange.com
Subject: RE: CEEDOD


here is how I call the procedure:

callp     $rtvREFERP('USR' :@userID :DSTUSR)


note: DSTUSR is a data structure.  The procedure will work correctly, if I 
change the caller program to define DSTUSR as a char field.


-----Original Message-----
From: Joe Pluta [mailto:joepluta@PlutaBrothers.com]
Sent: Wednesday, December 18, 2002 10:03 AM
To: midrange-l@midrange.com
Subject: RE: CEEDOD


> From: Lim Hock-Chai
>
> The caller did pass all three parms when I was testing it.
> However, the parm I passed is a data structure.  I did later find
> an discussion about CEEDOD wILL not work if the parm being passed
> is a data structure.  That particular discussion was date Jul
> 1999.  I wonder if IBM has corrected the problem.

This is not an IBM problem.  Your procedure expects three parameters.  You
cannot pass a single data structure and expect it to satisfy those three
parameters.  You can do one of the following:

1. Send each parameter individually
2. Change the prototype to accept only a single data structure
3. Add an interface procedure that accepts a data structure and passes the
elements of that data structure to the original procedure

Be very clear on this: you cannot pass a data structure to a procedure that
is expecting multiple values.

Joe

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