RE: Elementary SQL question

["Goodbar, Loyd (AFS-Water Valley)" <LGoodbar@xxxxxxxxxxxxxx>]

select a.custno, avg(count(b.*))
        from master a left join transactions b on (a.custn=b.custno)
        group by a.custno
        order by a.custno

Just in the save vein as the original suggestion..

Loyd

-----Original Message-----
From: rob@dekko.com [mailto:rob@dekko.com]
Sent: Friday, September 21, 2001 7:42 AM
To: midrange-l@midrange.com
Subject: RE: Elementary SQL question



And what about the customers with no transactions?

Rob Berendt

==================
A smart person learns from their mistakes,
but a wise person learns from OTHER peoples mistakes.



                    "Rolf Mittag"
                    <rm@r-m-e-d-v.de>         To:
<midrange-l@midrange.com>
                    Sent by:                  cc:
                    midrange-l-admin@mi       Fax to:
                    drange.com                Subject:     RE: Elementary
SQL question


                    09/21/2001 02:20 AM
                    Please respond to
                    midrange-l






out of my mind, not tested as I have no such files at hand

select <CustomerNumber>, avg(count(*)) from <transactionFile>
   group by <CustomerNumber>
   order by <CustomerNumber>

replace names within <> with the correct ones

hth Rolf