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Hey. Good question. At first blush: select a.key, avg(a.ts - (select min(b.ts) from theFile b where b.ts > a.ts and a.key = b.key)) from theFile a group by a.key but I can all but guarantee that that won't work. Maybe with a common table expression or a view.... signed, pondering in pennsylvania.... ;-) =========================================================== R. Bruce Hoffman, Jr. -- IBM Certified Specialist - AS/400 Administrator -- IBM Certified Specialist - RPG IV Developer "America is the land that fought for freedom and then began passing laws to get rid of it." - Alfred E. Neuman -----Original Message----- From: Joel Fritz <JFritz@sharperimage.com> To: MIDRANGE-L@midrange. com (E-mail) <MIDRANGE-L@midrange.com> Date: Friday, July 20, 2001 1:20 PM Subject: sql comparison between records >How do you do this in SQL? > >I have a file ordered by key value and a timestamp. There are multiple >records for each key value. I want to find the difference between time >stamps of successive records and calculate the average difference for a key >value group. I know, it's easy in RPG. I'm not trying to measure >programmer productivity. <g> >+--- >| This is the Midrange System Mailing List! >| To submit a new message, send your mail to MIDRANGE-L@midrange.com. >| To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. >| To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. >| Questions should be directed to the list owner/operator: david@midrange.com >+--- +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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