>Date: Wed, 13 Oct 1999 14:55:34 -0400 >From: Jon.Paris@halinfo.it > >The following will supply the date of the last day of the month for the month in >which InputDate falls. > > D InputDate D DATFMT(*ISO) > D Temp 3P 0 > > C Extract InputDate:*D Temp > C Eval Temp = Temp - 1 > C AddDur 1:*M InputDate > C SubDur 1:*D InputDate > >Thats's all there is to it!! Not quite all ... your code works fine if InputDate is already at the first of the month, although you could leave out the first two lines ... but Even if you subdur'd temp instead of 1 on the last line, you'd be off by one day - this gives the beginning of the next month. Sometimes. You also have to extract the days AFTER adding one month (finding the end of month containing say Jan 30 requires subtracting 28 or 29 days, not 30 days ...) Try this - it works for every date up to but not including dates in December 9999: D InputDate s D DATFMT(*ISO) D Temp s 3P 0 C AddDur 1:*M InputDate C Extrct InputDate:*D Temp C SubDur Temp:*D InputDate C return InputDate Barbara Morris +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: firstname.lastname@example.org +---
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