• Subject: RE: Last Day of Last Month
  • From: Chris Bipes <ChrisB@xxxxxxxxxxxxxxx>
  • Date: Wed, 13 Oct 1999 07:33:32 -0700

Take your date that you want to find the last day of, Say 19990901.  Add a
month to 19991001 and subtract a day.  Result = 19990930 or the last day of
any month, including leap years.
 

Christopher K. Bipes    mailto:ChrisB@Cross-Check.com
<mailto:ChrisB@Cross-Check.com>  
Sr. Programmer/Analyst  mailto:Chris_Bipes@Yahoo.com
<mailto:Chris_Bipes@Yahoo.com>  
CrossCheck, Inc.        http://www.cross-check.com
<http://www.cross-check.com/>  
6119 State Farm Drive   Phone: 707 586-0551 x 1102 
Rohnert Park CA  94928 Fax: 707 586-1884 

***** Note to Recruiters ***** 
I nor anyone that I know of is interested in any new and/or exciting
positions. Please do not contact me. 

 

-----Original Message-----
From: Brad McDaniel [mailto:BMCDANIEL@ABSBC.ORG]
Sent: Wednesday, October 13, 1999 6:31 AM
To: 'midrange-l@midrange.com'
Subject: Last Day of Last Month



I am writing some CL's to automate some monthly jobs that are usually
submitted through user menus.  This particular CL submits a job with the
prior month and year as the parms (let's say &YEAR (4) and &MONTH (2)).
Then, the CL does a STRQMQRY with the year, month, and day of the last day
of that month.  Does anyone have a sample of the easiest way to figure out
the last day of a particular month (i.e.  if run today, the year and month
would be 1999 09, and the CL would need to pass 19990930 to the query.)?

I know the method for passing parms with STRQMQRY, I am just wondering if
anyone has some code laying around that gives you the last day of the month
(accounting for leap years also).

Thanks   

Brad McDaniel 
Information Services 
Annuity Board, SBC 
http://www.absbc.org <http://www.absbc.org>  
214-720-6546 

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