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  • Subject: RE: A Math Question
  • From: "Benoit, Thomas A." <TABenoit@xxxxxxxxxxxxxx>
  • Date: Sat, 10 Jul 1999 13:01:58 -0400

The ranges you have seen (20MB to 160MB) may seem to be inconsistent - but -
the answer is relative to the efficiency of the blocking of the data.  The
math becomes simple when you know that the IRG (inter record gap) is .75
inch or a waste of approx. 4687.5 bytes.  Divide 180,000,000 [ max for 2400'
reel] by your (block length + 4687.5) and you will find out how many blocks
of data will fit.  

        -----Original Message-----
        From:   Ed Tate [SMTP:etate01@sun.hazelwood.k12.mo.us]
        Sent:   Friday, July 09, 1999 4:32 PM
        To:     MIDRANGE-L
        Subject:        A Math Question

        Does anyone know approximately how much data (ie: MB or GB or ???)
fits on a
        big 9 track tape @ 6250bpi?

        Ed Tate (etate01@sun.hazelwood.k12.mo.us)
        Coordinator of Technology
        Hazelwood School District
        15955 New Halls Ferry
        Florissant, MO  63031
        314-953-5090


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