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The ranges you have seen (20MB to 160MB) may seem to be inconsistent - but - the answer is relative to the efficiency of the blocking of the data. The math becomes simple when you know that the IRG (inter record gap) is .75 inch or a waste of approx. 4687.5 bytes. Divide 180,000,000 [ max for 2400' reel] by your (block length + 4687.5) and you will find out how many blocks of data will fit. -----Original Message----- From: Ed Tate [SMTP:etate01@sun.hazelwood.k12.mo.us] Sent: Friday, July 09, 1999 4:32 PM To: MIDRANGE-L Subject: A Math Question Does anyone know approximately how much data (ie: MB or GB or ???) fits on a big 9 track tape @ 6250bpi? Ed Tate (etate01@sun.hazelwood.k12.mo.us) Coordinator of Technology Hazelwood School District 15955 New Halls Ferry Florissant, MO 63031 314-953-5090 +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +--- +--- | This is the Midrange System Mailing List! | To submit a new message, send your mail to MIDRANGE-L@midrange.com. | To subscribe to this list send email to MIDRANGE-L-SUB@midrange.com. | To unsubscribe from this list send email to MIDRANGE-L-UNSUB@midrange.com. | Questions should be directed to the list owner/operator: david@midrange.com +---
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