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  2. MIDRANGE-L
  3. February 1999

RE: date difference

I'm not sure it works quite that way.  20000101 sub 1999365 is not 1. 


>Depending on the way in which you want the difference expressed, I would 
>suggest perhaps a CL program that accepts the two dates, does a CVTDAT to
> Julian (on both dates), then subtracts one from the other.  The
>difference  between the two dates would then be the number of days.
-- 
-----------------------------------------------------------
boothm@ibm.net
Booth Martin
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