Fw: how to create unsigned hexadecimal initial value

I think this one got lost too.

----- Original Message -----
From: Leif Svalgaard <leif@leif.org>
To: <MI400@midrange.com>
Sent: Saturday, August 26, 2000 7:05 AM
Subject: Re: how to create unsigned hexadecimal initial value


> From: <rjd@us.ibm.com>
> Subject: Re: how to create unsigned hexadecimal initial value
>
>
> > I think even the more recent examples are easy to explain in terms of the
> > definition I gave for H literals.
>
> Bob, here is your definition:
> "
> The H literal is used to specify a signed integer value.  The format is
> H'h1h2h3h4', where h1, h2, h3, and h4 are hexadecimal digits.  If fewer
> than 4 digits are specified, leading zeros (0x00) are prepended.  For
> example,  H'FF' is equivalent to H'000000FF'.  The sign of the value is
> determined by the value of h1.  The largest positive value that can
> specified is 2147483647 (H'7FFFFFFF').  [Note:  this is not unlike integer
> literals in  C++.  For example, 0xff in the following statement represents
> the value 255, not -1:  int h = 0xff;]
>
> The length of an H literal is the minimum number of bytes needed to
> represent the value.  The length of a negative value is always 4 bytes.
> "
>
> I'll try to rewrite it the way I think you meant it:
> "
> The H literal is used to specify an integer value.  The format is
> H'h1h2h3h4h5h6h7h8', where h1, h2, h3, h4, h5, h6, h7, and h8 are
> hexadecimal digits.  If fewer than 8 digits are specified, leading zeros
> (0x00) are prepended.  For example,  H'FF' is equivalent to H'000000FF'.
> The sign of the value is determined by the value of h1.  The largest
> positive value that can specified is 2147483647 (H'7FFFFFFF'). The
> smallest negative value that can be specified is -2147483648
> (H'80000000').
> The length of an H literal is always 4 bytes.
> ".
>
> The problem Gene had has really nothing to do with the H literal, but is
> simply that one cannot initialize an unsigned integer with a negative
> value regardless of its size.
>
>
>

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