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Hello, you may use: char(numFld) like '1%' Dan wrote: > On 12/6/05, Marshall Dunbar/DPS <marshall@xxxxxxxxxxx> wrote: > >> I'm on V5R2 and if I try to use the LIKE predicate on a numeric field, I >> get the same error message, >> > > > Not an SQL expert by any means, but I thought the Like predicate could not > be used on numeric fields. > > - Dan >
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