Hello,
you may use: char(numFld) like '1%'

Dan wrote:
> On 12/6/05, Marshall Dunbar/DPS <marshall@xxxxxxxxxxx> wrote:
>   
>> I'm on V5R2 and if I try to use the LIKE predicate on a numeric field, I
>> get the same error message,
>>     
>
>
> Not an SQL expert by any means, but I thought the Like predicate could not
> be used on numeric fields.
>
> - Dan
>   



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