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  • Subject: How to setup classpath in WebSphere 2.0 to include ToolBox?
  • From: "Bruce Jin" <brucej@xxxxxxxxxxxxxxxxxxxx>
  • Date: Wed, 7 Feb 2001 15:45:24 -0600

The following servlet tries to create an AS400 object using the AS400 class
in jt400.zip file.  The output of this servlet is as follows:

---------browser output -------------------------------
Create AS400 Object...
Error: java.lang.ClassNotFoundException: com.ibm.as400.access.AS400
Are we done?

I verified the following:
    1. The CLASSPATH on the as400 V4R5 is
‘/Qibm/ProDdata/Http/Public/jt400/lib/jt400.zip’, (WRKENVVAR
LEVEL(*SYS)).
    2. The Use System Classpath in Setup Java Engine is default to ‘Yes’
(WAS Server Manager)
    3. the jt400.zip file is in Qibm/ProDdata/Http/Public/jt400/lib.

What else should be done to make this servlet find jt400.zip?

TIA
Bruce





import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import com.ibm.as400.access.*;

public class CallRPG1 extends HttpServlet {
     public void doGet(HttpServletRequest req, HttpServletResponse res)
   throws ServletException, IOException    {

     res.setContentType("text/html");
     PrintWriter out = res.getWriter();
     out.println("<html> <head> <title> Title  </title> </head> <body>");

     out.println("Create AS400 Object... <br> ");
     try {
        AS400 as400 = new AS400();
     }
      catch (Exception e) {
        out.println("Error: " + e + "<br>");
    }

     out.println("Are we done? ");

     out.println("</body> </html>");
     out.close();
 }
}


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