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Hello Barbara,
thanks a lot for taking time to try out and answer!
Am 16.08.2022 um 22:43 schrieb Barbara Morris <bmorris@xxxxxxxxxx>:
Can you show the code you're using to typecast the char pointer?
No longer necessary, and no longer existing in its broken form. :-)
I'll publish the project on Github when the first part is working.
p = (char *)&keys;
I have done some mixup here. Sometimes I confuse * and &. Additionally, I apparently can't correctly memorize the correct syntax for typecasts when pointers are involved.
My bad!
:wq! PoC
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