Re: C++0x syntax question

Hi Kelly,

According to the C++ standard (see below), the error messages are expected.
'typename' should be added.

14.6 Name resolution

2 A name used in a template declaration or definition and that is
dependent on a template-parameter is assumed not to name a type
unless the applicable name lookup finds a type name or the name
is qualified by the keyword typename.

The diagnostic message from ILE C++ compiler with option LANGLVL
(*EXTENDED0X) is not as clear as the messages from g++ compiler.

We need more investigation on the reason why the compiler does not generate
diagnostic message without LANGLVL(*EXTENDED0X).

Thanks.


Qian Ren (Jarod)



From: Kelly Beard <kenverybigliar@xxxxxxxxx>
To: "Bare Metal Programming IBM i (AS/400 and iSeries)"
<c400-l@xxxxxxxxxxxx>
Date: 09/13/2017 12:06 AM
Subject: Re: [C400-L] C++0x syntax question
Sent by: "C400-L" <c400-l-bounces@xxxxxxxxxxxx>



per my question, this does seem to be a change in syntax in the language.
g++ is more clear and complete in it's error reporting. For the newer
stuff, the word "typename" should appear appear in front of the offending
line. The corrected code is:

#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
#include <vector>
#include <unistd.h>

using namespace std;


template<typename T> vector<T> split(const T & str, const T & delimiters)
{
vector<T> v;
typename T::size_type start = 0;
size_t pos = str.find_first_of(delimiters, start);
while (pos != T::npos) {
if (pos != start) { // ignore empty tokens
v.push_back(str.substr(start, pos - start));
}
start = pos + 1;
pos = str.find_first_of(delimiters, start);
}
if (start < str.length()) { // ignore trailing delimiter
v.push_back(str.substr(start, pos - start));
}
return v;
}


int main(int argc, char* argv[])
{
string str = "this,is,a,test, of whatever, like, ok.";
vector<string> v = split<string>(str, ", ");
for (int i = 0; i < v.size(); ++i) {
cout << v[i] << endl;
}
}


On Tue, Sep 12, 2017 at 10:38 AM, Kelly Beard <kenverybigliar@xxxxxxxxx>
wrote:

Take away the *EXTENDED0X option and it compiles just fine.

On Tue, Sep 12, 2017 at 10:21 AM, Mark S Waterbury <
mark.s.waterbury@xxxxxxxxxxxxx> wrote:

Kelly,

Did this code ever compile on IBM i under previous versions of the IBM
ILE C++ compiler?

IBM does not strictly follow the ANSI standards for either C or C++ ...

You could also install the open-source GCC compiler and it would

probably

compile this code for you ... of course, the resulting object code would
run under PASE ...

Mark

On 9/12/2017 10:57 AM, Kelly Beard wrote:

I am attempting to compile the following code under the newer compiler
under V7R3 and the LANGLVL *EXTENDED0X option enabled. I am using the
5799PTL 'icc' compiler front-end to do this. The command default for
CRTCPPMOD has been altered to always have *EXTENDED0X on by default. I
am
getting this:

"testme.cpp", line 14.18: CZP0130 (30) "start" is not declared.

The offending line looks like:

T::size_type start = 0;

So, is there a change to the C++11 syntax here? Thanks in advance, as
always. Here is the test program.

#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
#include <vector>
#include <unistd.h>

using namespace std;


template<typename T> vector<T> split(const T & str, const T &

delimiters)

{
vector<T> v;
T::size_type start = 0;
size_t pos = str.find_first_of(delimiters, start);
while (pos != T::npos) {
if (pos != start) { // ignore empty tokens
v.push_back(str.substr(start, pos - start));
}
start = pos + 1;
pos = str.find_first_of(delimiters, start);
}
if (start < str.length()) { // ignore trailing delimiter
v.push_back(str.substr(start, pos - start));
}
return v;
}


int main(int argc, char* argv[])
{
string str = "this,is,a,test, of whatever, like, ok.";
vector<string> v = split<string>(str, ", ");
for (int i = 0; i < v.size(); ++i) {
cout << v[i] << endl;
}
}

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