Re: Converting packed decimal to a char array

Big-big thanks to Barbara and Tim.

The result is:

void printdec(void *A, int Len, int Prec)
{
decimal(63,0) fulldec ;
int offset, bytes ;

bytes = (Len / 2) + 1;
offset = 32 - bytes;
fulldec = 0;
memcpy(((char *) &fulldec) + offset, A, bytes);
printf("%0*.*D(63,*)\n", (Len + 1), Prec, Prec, fulldec) ;
}

is exactly what I've been looking for.

Jevgeni.


On Tue, Mar 17, 2015 at 3:58 AM, Barbara Morris <bmorris@xxxxxxxxxx> wrote:

On 2015-03-16 12:46, Barbara Morris wrote:

Oops, it should just be fulldec, not s.fulldec. (I had put fulldec into a
struct with a char following so I could easily check for storage overrun in
the debugger.)

void printdec(void *A, int Len, int Prec)
{
decimal(63,0) fulldec;
int offset;
int bytes = (Len / 2) + 1;
// Move packed number to a 63,0 variable.
offset=32 - bytes;
fulldec=0;
memcpy(((char *) &fulldec)+offset, A, bytes);
// Now print it.
printf("%D(63,*)\n", Prec, fulldec) ;
}


--
Barbara

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