Re: Converting packed decimal to a char array

[Jevgeni Astanovski <jevgeniast@xxxxxxxxx>]

Big-big thanks to Barbara and Tim.

The result is:

void printdec(void *A, int Len, int Prec)
{
  decimal(63,0) fulldec ;
  int offset, bytes ;

  bytes = (Len / 2) + 1;
  offset = 32 - bytes;
  fulldec = 0;
  memcpy(((char *) &fulldec) + offset, A, bytes);
  printf("%0*.*D(63,*)\n", (Len + 1), Prec, Prec, fulldec) ;
}

is exactly what I've been looking for.

Jevgeni.


On Tue, Mar 17, 2015 at 3:58 AM, Barbara Morris <bmorris@xxxxxxxxxx> wrote:
> On 2015-03-16 12:46, Barbara Morris wrote:
>
> Oops, it should just be fulldec, not s.fulldec. (I had put fulldec into a
> struct with a char following so I could easily check for storage overrun in
> the debugger.)
>
>  void printdec(void *A, int Len, int Prec)
>  {
>    decimal(63,0) fulldec;
>    int offset;
>    int bytes = (Len / 2) + 1;
>     // Move packed number to a 63,0 variable.
>     offset=32 - bytes;
>     fulldec=0;
>     memcpy(((char *) &fulldec)+offset, A, bytes);
>     // Now print it.
>     printf("%D(63,*)\n", Prec, fulldec) ;
>  }
>
>
> --
> Barbara
>
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