Re: digitsof in a declaration

Hi all,

Mark - Erik's code _does_ include decimal.h.

Erik - This appears to be a bug in the C compiler.

These declarations work:

char periodString[digitsof(var)];
char periodString[10 + 1];

but this does not:

char periodString[digitsof(var) + 1];

It appears to be a problem with using the digitsof macro in an expression
on the array declaration.

As a workaround you could just allocate the storage:

char *periodString = (char *)malloc(digitsof(myrec.DECFIELD) + 1);

Thanks,

Aaron Albertson

c400-l-bounces+albertaa=us.ibm.com@xxxxxxxxxxxx wrote on 05/10/2011
10:06:25 AM:

From: "Mark S. Waterbury" <mark.s.waterbury@xxxxxxxxxxxxx>
To: C programming iSeries / AS400 <c400-l@xxxxxxxxxxxx>
Date: 05/10/2011 10:10 AM
Subject: Re: [C400-L] digitsof in a declaration
Sent by: c400-l-bounces+albertaa=us.ibm.com@xxxxxxxxxxxx

Hi, again, Erik:

Further searching of the InfoCenterI found this:

To use the decimal digitsof, and precisionof macros in your code,
you must specify

#include <decimal.h>

in your ILE C source.

(Did you even _try_ to search for an answer, e.g. in the InfoCenter,
before asking on the C/400 list?)

HTH,

Mark S. Waterbury

> On 5/10/2011 10:46 AM, Erik Olsson wrote:

Anyone understand why I can't use the digitsof keyword in a
declaration? It's based on a decimal field in a struct that is known
at compile time so I don't see the problem.

#include<decimal.h>
#include</source/yada/tabledefs/myfile.h>

/* ... */

FLXDXYZ_MYFILE_MYFILE_both_t myrec;

char periodstring[digitsof(myrec.DECFIELD) + 1];

I get this: "Integral constant expression with a value greater than
zero is required"


Best wishes,
Erik

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