Re: array of strings and NULL termination

On Thu, 2008-11-20 at 10:42 -0600, Elvis Budimlic wrote:

Given this code:



===============================================================

#include <stdio.h>



void testFunc(char ** array)

{

char * p;

int i;

for (i = 0, p = array[0]; p != NULL; p = array[++i])

printf("%s \n",p);

}



void main(void)

{

char * strings[] = {"First", "Second", "Third", "Fourth", "Fifth"};

testFunc(strings);

}

===============================================================



Can I rely on the pointer beyond the last pointer in the array to be NULL?

Nope.

I mean, does the compiler/runtime guarantee that the 6th element in the
array is initialized to NULL?

What sixth element? I only see strings[] defined with five elements.
Code, instead, ...

char * strings[]
= {"First", "Second", "Third", "Fourth", "Fifth", NULL};

It works in this testcase, but I wanted to make sure I'm not just getting
lucky.

I would have said that you got particularly unlucky, but to each his
own.

Cheers,
Terry.

Thanks.



Elvis



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