Couple of small things I forgot:

On Wed, 11 Jun 2008, James Rich wrote:

s1 = malloc (sizeofbuffer * sizeof(char));

This really needs a cast to be proper:

s1 = (char) malloc (sizeofbuffer * sizeof(char));

The thing I forgot to mention is that you must remember to free the allocated memory when you are done with it. If you don't, you'll have a "memory leak" in your program - memory that is allocated but unreachable by any program code. So free it like this:

free (s1);

James Rich

It's not the software that's free; it's you.
- billyskank on Groklaw

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