On 02/10/2004, at 5:05 AM, David C. Shea wrote:

When I look at the dump, I see:

&RRN9              *DEC               15 0        '        '
1E0000000000000F

What should the format of the passed variable from the CL be?

CL is expecting a packed decimal value so you better make damned sure that's what you return from C.


In the C program:
.
.
int main(int argc, char * argv[])
.
.
*argv[2] = riofb_fwd->rrn;
.
.
I'm guessing that I need to convert a field format someplace...

Your problem is that C has no idea what *argv[2] is. It is just a pointer to some chunk of storage. The only thing C knows at this point is that riofb_fwd->rrn is an unsigned long integer so it assigns the integer value to the bytes addressed by the pointer. But because C rather stupidly treats char as a numeric type and *argv[2] is a char it copies (via assignment) only the last byte of the unsigned long. The value in riofb_fwd->rrn was probably 30 which is x'0000001E' (or 0x1e since this is the C list). You can see from the dump that the 1E has been assigned to the first byte of the packed decimal. x'E' is not a valid value in a packed decimal (digits 0 to 9 only) thus the decimal data error.


You need to ensure C understands the receiving data type so it can convert correctly. The following code

decimal(15,0) * rrn = (decimal(15,0)*)argv[2];
*rrn = riofb_fwd->rrn;

will do it. If you don't do it this way you'll have to do something ugly like passing character values or convert to decimal in the C (by assigning to an appropriate decimal variable) and copy the correct number of bytes into your caller's storage. Doesn't C suck?

Regards,
Simon Coulter.
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