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Hi,
I am trying to convert a statement that turns off the first four bits in a
single byte field to free-form and am unsure of the best way to do that.
Original statement:
C BITOFF '0123' BYTE
Create a hex field containing the bits that you want to keep on. The
%bitand() BIF will return a new byte where only those bits are copied from
the original.
The old opcodes (like your example above) confuse me, so I hope I'm right,
but this is what I suggest:
byte = %bitand(x'0F': BYTE);
How this works is based on copying the bits that are on in BOTH bytes to
the result. For the sake of example, let's say that BYTE contains the
letter R, which is x'D9' in EBCDIC (I just picked this as a random value)
You'll have the following in binary:
x'0F' = 00001111
x'D9' = 11011001
So, it copies the bits that are in on BOTH fields, yielding:
00001001
In other words, since I used x'0F' (which has the first 4 bits off, and
the last 4 bits on) it copies just the last 4 bits of the field, and sets
the rest of them off.
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