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C++ is a special case.  In C++ OO design is a convention you can choose to
follow or not.  My first C teacher used to say "C doesn't care."  It applies
to C++ too.  

> -----Original Message-----
> From: Steve Richter [mailto:srichter@xxxxxxxxxxxxx]
> Sent: Tuesday, May 06, 2003 11:21 AM
> To: RPG programming on the AS400 / iSeries
> Subject: RE: what is object oriented programming
> 
> 
> 
> 
> -----Original Message-----
> From: rpg400-l-bounces@xxxxxxxxxxxx
> [mailto:rpg400-l-bounces@xxxxxxxxxxxx]On Behalf Of Hans Boldt
> Sent: Tuesday, May 06, 2003 1:37 PM
> To: rpg400-l@xxxxxxxxxxxx
> Subject: Re: what is object oriented programming
> 
/****************   Snip ***********************************/
> 
> Hans replied:
> >To put it simply, yes, a data structure is just a buffer definition.
> 
> Is a c++ class with public data members also just a buffer 
> definition?  If
> the members are all private, but a public member function 
> allows direct
> access to the data member ( returns a mutable reference ), is the
> class/struct also just a buffer definition?  Sounds like you 
> would say yes.
> 
> The point is that it is how the struct is used and the design 
> of the procs
> that access the struct, rather than what the compiler allows 
> or does not
> allow, that provides the real world definition of an object.
> 
> -Steve
> 
> 
> 
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