Re: the word 'static'

Specifically: Your $Exit is a pointer to the area in memory that
contains the *IN03 indicator.  Indicators are global to your job
(or close enough not to matter).  When you return from the 
subprocedure the indicator memory area is not changed.  

In your example, using $Exit and *IN03 are exactly the same.  You
can expect $Exit to do anything/everything *IN03 would do.  It's the
magic of pointers (although you may not consider a DS that remaps
the Indicators to be pointers, I believe that's what's really going
on behind the scenes).

And, yes, to me Subprocedure and Subroutine are synonyms.

Regards,

Jim Langston

Me transmitte sursum, Caledoni!

Patrick Conner wrote:
> 
> Jim,
> 
> Thanks for the trivia. That was interesting. However, based
> on what is below I have a question.
> The scenario is:
> I have a subprocedure that displays a screen. I have a DS
> that maps the indicator variables. $Exit maps *in03. When
> the user presses F3, $Exit = *on and I exit the
> subprocedure. When I return to the subprocedure $Exit is
> still equal to *on.
> The question is:
> Since I did not define $Exit as 'Static' why is it not
> reset?
> 
> !!! I'm assuming you mean subprocedure where subroutine is
> mentioned. !!!
> On Fri, 01 Jun 2001 15:27:58 -0700
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