Re: PHP using ODBC not liking like

[Sam_L <lennon_s_j@xxxxxxxxxxx>]

Caveat: I'm not a PHP expert.
I think it's likely that your like array value is padded right with 
blanks and you'll have to remove them. Not sure of syntax but maybe 
DEBAC LIKE %TRIM(?).

Sam

On 9/26/2022 11:50 PM, Don Brown via MIDRANGE-L wrote:
> I an trying to use a LIKE in my SQL to allow searching for the result.
>
>  From Run SQL Scripts this works exactly as expected
>
> select * from mfsdta/mfsdebpf
>    where debcoy = 1 and debac like 'A%' and debact = 'A'
>    fetch first 10 rows only;
>
> But from PHP running on the IBMi using the toolkitservice I have
>
>                  $conn = getToolkitServiceForCurrentUser();
>                  $sql = "select * from "
>                          . MFS_LIBRARY . ".MFSDEBPF "
>                          . " where DEBCOY = ? and DEBAC like ? and debact =
> ? "
>                          . " order by DEBAC "
>                          . " fetch first 10 rows only";
>
>                  $values = array();
>                  $values[0] = $company;
>                  $values[1] = $search . "%";
>                  $values[2] = $status;
>                  print_r($values);
>                  $stmt = prepareAndExecute($conn, $sql, $values);
>
> The $values array have these values
>
> Array ( [0] => 1 [1] => A% [2] => A )
>
> No errors are received but no records either.
>
> If I change the where to use and DEBAC >= ?  then I get records returned
> so it has to be the way I am formatting the variable with the % sign.
>
> As a separate question I can't find any log file that may hold the answer
> - any suggestions ????
>
> Thanks
>
> Don
>
>
>
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