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I tried these three steps and it worked:

1) STRQSH
2) cd /QSYS.LIB/<libraryname>.LIB/QCLSRC.FILE
3) grep -ic logclpgm * | awk -F":" '$2 == 0 {print $1}'

Logic:

a) grep (from FreeBSD manual page):

-i, --ignore-case
Ignore case distinctions in both the PATTERN and the input
files.
...
-c, --count
Suppress normal output; instead print a count of matching lines
for each input file. With the -v, --invert-match option (see
below), count non-matching lines.

b) awk

-F "field-separator" (use the colon. grep output with above options is
filename:count

matching pattern $2 == 0 : when the second field is zero
(logclpgm was not found)
{action} : print the first field (the member name).




El Fri, 11 Nov 2016 10:00:06 -0600
broehmer@xxxxxxxxxxxxxxx escribió:
Hello All,

I've looked thru a ton of GREP documentation and the archives
to find out how to find source members NOT having that text.
Specifically, I'm reviewing our QCLSRC member to see if the
member has "LOGCLP" and hoping to list only those not having
that command.
It would appear that the key is to use the exit side of the result
and I cannot find any example of how to do that.
Does anyone have an example showing how to list members
NOT having something?

This shell command adds to a file of all that have the phrase but I don't
know how to turn it into one that does not find the text.

qsh cmd('grep -l "LOGCLP" /qsys.lib/cdsrclib.lib/qclsrc.file/* >
/qsys.lib/rrpg.lib/myfile.file/myfile.mbr')

Thanks for any reply,

Bill


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