Re: GREP - source members not containing...

[Manuel Chaviano <manny@xxxxxxxxxxxx>]

I tried these three steps and it worked:

1) STRQSH
2) cd /QSYS.LIB/<libraryname>.LIB/QCLSRC.FILE
3) grep -ic logclpgm * | awk -F":" '$2 == 0 {print $1}'

Logic:

a) grep (from FreeBSD manual page):

       -i, --ignore-case
              Ignore  case  distinctions  in  both  the  PATTERN and the input
              files.
...
        -c, --count
              Suppress  normal output; instead print a count of matching lines
              for each input file.  With the -v,  --invert-match  option  (see
              below), count non-matching lines.

b) awk 

	-F "field-separator" (use the colon. grep output with above options is
                              filename:count

        matching pattern $2 == 0 : when the second field is zero 
                                   (logclpgm was not found)
        {action} : print the first field (the member name).




El Fri, 11 Nov 2016 10:00:06 -0600
broehmer@xxxxxxxxxxxxxxx escribió:
> Hello All,
>
> I've looked thru a ton of GREP documentation and the archives
> to find out how to find source members NOT having that text.
> Specifically, I'm reviewing our QCLSRC member to see if the
> member has "LOGCLP" and hoping to list only those not having
> that command.
> It would appear that the key is to use the exit side of the result
> and I cannot find any example of how to do that. 
> Does anyone have an example showing how to list members 
> NOT having something?
>
> This shell command adds to a file of all that have the phrase but I don't
> know how to turn it into one that does not find the text.
>
> qsh cmd('grep -l "LOGCLP" /qsys.lib/cdsrclib.lib/qclsrc.file/* > 
>        /qsys.lib/rrpg.lib/myfile.file/myfile.mbr') 
>
> Thanks for any reply,
>
> Bill 
>
>
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