Re: SQL Sum(Distinct()) -- MIDRANGE-L

I know the OP has gotten his answer. But I'm wondering. If there's no
index by ONRCU and ORDAM, which is going to perform better, your group by
or my max function suggestion?

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Michael Schutte
Admin Professional

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Charles Wilt
<charles.wilt@gma
il.com> To
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cc

06/21/2010 11:16 Subject
AM Re: SQL Sum(Distinct())

Please respond to
Midrange Systems
Technical
Discussion
<midrange-l@midra
nge.com>

Forgot to add ORDAM to the group by:
with OrderSummary as (select h.ONRCU, h.ORDAM,
sum(d.ITNSA) as SumItmAmt
from ORHDR H join ORDTL D using (ONRCU)
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO
group by h.ONRCU, h.ORDAM)
select sum(ORDAM), sum(SumItmAmt) into :ORDAM, :ITNSA
from OrderSummary

Note that the MAX() function used by Michael is a alternative to
putting ORDAM in the group by...

However, I prefer not to use that technique, as you aren't really
looking for the max. Assuming ONRCU is unique in the header, grouping
by ONRCU, ORDAM is still unique.

Charles

On Mon, Jun 21, 2010 at 11:09 AM, Charles Wilt <charles.wilt@xxxxxxxxx>
wrote:

Jeff,

Using aggregate functions across different join levels of data is
always doing to be a problem...

You could use a Common Table Expression to bring the data to the same

level..

with Hdr as (select CUSNR, ROUTE, STOPX, SHPDTISO
SUM(ORDAM) as SumOrdAmt
from ORHDR
where CUSNR = :CUSNR and
ROUTE = :ROUTE and
STOPX = :STOPX and
SHPDTISO = :SHPDTISO)
, dtl as (select CUSNR, ROUTE, STOPX, SHPDTISO
SUM(ITNSA) as SumItmAmt
from ORDTL
where CUSNR = :CUSNR and
ROUTE = :ROUTE and
STOPX = :STOPX and
SHPDTISO = :SHPDTISO)
select SumOrdAmt, SumItmAmt into :ORDAM, :ITNSA
from hdr join dtl using(CUSNR, ROUTE, STOPX, SHPDTISO)

An alternative format that might be easier to understand

with OrderSummary as (select h.ONRCU, h.ORDAM,
sum(d.ITNSA) as SumItmAmt
from ORHDR H join ORDTL D using

(ONRCU)

Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO
group by h.onrcu)
select sum(ORDAM), sum(SumItmAmt) into :ORDAM, :ITNSA
from OrderSummary

HTH,
Charles

On Mon, Jun 21, 2010 at 10:32 AM, Jeff Crosby <jlcrosby@xxxxxxxxxxxxxxxx>

wrote:

Been a while since I've asked an SQL question, so I'm due. :)

I will soon, I think, have a need within an RPG program to get a couple

pieces of summary information from an order header/detail pair of files.
One piece from the header file and one piece from the detail file. I

can

get the 2 pieces separately like this:

Exec SQL
Select SUM(ORDAM)
Into :ORDAM
From ORHDR
Where CUSNR = :CUSNR and
ROUTE = :ROUTE and
STOPX = :STOPX and
SHPDTISO = :SHPDTISO;

Exec SQL
Select SUM(d.ITNSA)
Into :ITNSA,
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

I wondered if I could get the 2 pieces with a single statement, so I

tried

this:

Exec SQL
Select SUM(d.ITNSA),
SUM(h.ORDAM)
Into :ITNSA,
:ORDAM
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

It executed, but the RPG field ORDAM was waAAAyyy off because field

h.ORDAM

from the header file was summed for each record in the detail file. I
understand why that is and it makes sense. I did some googling and came

with this, using Distinct:

Exec SQL
Select SUM(d.ITNSA),
SUM(Distinct(h.ORDAM))
Into :ITNSA,
:ORDAM
From ORDTL d Join ORHDR h on d.ONRCU = h.ONRCU
Where h.CUSNR = :CUSNR and
h.ROUTE = :ROUTE and
h.STOPX = :STOPX and
h.SHPDTISO = :SHPDTISO;

That seemed to me like it would have a problem, because 2 selected order
header records COULD have the same h.ORDAM value. Won't happen often,

but

it can and does happen sometimes. If I understand Distinct right, it

would

only include one of them in the Sum function. So I did some testing and
found that to be true.

So is there a way to do what I want in one statement? The flip side of

that

is, if the statement is very complex, I would rather do it in 2

statements

because I believe in KISS.

Thanks.

--
Jeff Crosby
VP Information Systems
UniPro FoodService/Dilgard
P.O. Box 13369
Ft. Wayne, IN 46868-3369
260-422-7531
www.dilgardfoods.com

The opinions expressed are my own and not necessarily the opinion of my
company. Unless I say so.
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