×
The internal search function is temporarily non-functional. The current search engine is no longer viable and we are researching alternatives.
As a stop gap measure, we are using Google's custom search engine service.
If you know of an easy to use, open source, search engine ... please contact support@midrange.com.
Dina
That appears to be identical to the original statement. But one doesn't
ask questions after something works, correct?
I recommend a different syntax for joining tables - use the JOIN
keyword. When you use a comma-separated list and the WHERE clause, you
are putting 2 different functions into one clause - I prefer reserving
the WHERE clause for selectivity.
So I would rewrite your statement as here -
SELECT A.FLD12, B.FLD12
FROM LIB1.TABLE1 A JOIN LIB2.TABLE1 B
ON
A.KEYFLD1 = B.KEYFLD1 AND
A.KEYFLD2 = B.KEYFLD2
dina ramzy wrote:
Thanks a lot for you help
I might have typed something wrong in my session but the below statement works fine now :)
SELECT A.FLD12, B.FLD12
FROM LIB1.TABLE1 A, LIB2.TABLE1 B
WHERE
A.KEYFLD1 = B.KEYFLD1 AND
A.KEYFLD2 = B.KEYFLD2
This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact
[javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.
midrange.com
