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  3. November 2008

Re: SQL TIMESTAMPDIFF

Jeff Young wrote:
According the the V5R3 SQL Reference manual, this built in function should return the difference between 2 timestamps.
[...] The SQL command I am attempting to build is :
SELECT a.BBPCPK, a.BBPCPKD, a.BBASSIGN, TIMESTAMPDIFF(2, (DIgits(a.bbcctd) || digits(a.bbcctt)), (DIgits(b.bbcctd) || digits(b.bbcctt))) diff FROM VOCTRACK a join voctrack b on a.bbassign= b.bbassign WHERE a.bbcctd = 20081016 and a.bbcode = 'STR' and b.bbcode = 'END'
The concatanation of variables for parameter 2 and 3 do result in valid timestamp values.

Instead of TIMSTAMPDIFF(diffUnits, timestamp1, timestamp2), I think you want TIMSTAMPDIFF(diffUnits, timestamp1 - timestamp2).

The way I read the docs, TIMESTAMPDIFF converts the duration string which is the result of timestamp subtraction into a single unit, it doesn't actually calculate the difference.

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