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It seems most RAND() functions return [0,1) (1 is not included)

That way, rand() * N gives you integers [0,N-1].

Charles Wilt
Software Engineer
CINTAS Corporation - IT 92B
513.701.1307

wiltc@xxxxxxxxxx


-----Original Message-----
From: midrange-l-bounces@xxxxxxxxxxxx [mailto:midrange-l-
bounces@xxxxxxxxxxxx] On Behalf Of Adam Glauser
Sent: Wednesday, February 13, 2008 10:05 AM
To: midrange-l@xxxxxxxxxxxx
Subject: Re: SQL RAND function question

lgoodbar@xxxxxxxxxxxxxx wrote:
Have you filed a PMR? This is reproducible.
<snip>
exec sql insert into loyd/randno (number)
values(cast(rand()*11 as decimal(2,0)));
<snip>
Results in SQL:
select number, count(*) from loyd/randno group by number order by 1

....+....1....+....2....+....3
NUMBER COUNT ( * )
0 90,751
1 90,312
2 91,026
3 90,885
4 91,061
5 91,168
6 90,453
7 91,287
8 90,914
9 90,861
10 91,245
11 37
******** End of data ********

This is to be expected given the way RAND() works in DB2. It could be
clearer in the documentation, but if you see my earlier post
http://archive.midrange.com/midrange-l/200802/msg00481.html and Chuck's
post http://archive.midrange.com/midrange-l/200802/msg00496.html, I
think your results will make more sense. In your case, since you are
truncating the result of the multiplication by using cast(), 11 will
only show up if RAND() returned _exactly_ 1.
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