Re: problems with iconv

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On 08/04/2006, at 6:34 AM, Scott Klement wrote:

It's true that there might be input that doesn't get translated (if the
parameter is longer than what will fit into the output buffer) but Idon't
see how it could overwrite another area of memory...

It won't overwrite storage but it may print more than it should.Because you set the input length to strlen(argv[1]) you are effectivelyremoving the null-terminator on the input string. Thus iconv() will notinclude a null-terminator in the converted output. Thus printf() on theASCII string may print additional characters that just happen to be inoutbuf. Not a big deal in a trivial example like this but in a loop itbecomes apparent. Easy to fix though.


Regards,
Simon Coulter.
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Re: problems with iconv_open